类别:程序开发
日期:2022-09-24 浏览:2074 评论:1
方法一 注:需要.net 3.5框架的支持
string s = "101,102,103,104,105,101,102,103,104,105,106,107,101,108"; s = string.Join(",", s.Split(',').Distinct().ToArray());
方法二
class Program { static void Main(string[] args) { string result=""; string str = "101,102,103,104,105,101,102,103,104,105,106,107,101,108"; ArrayList list = array(str); for (int i = 0; i < list.Count;i++) { if (i == list.Count - 1) { result += list[i]; } else { result += list[i] + ","; } } Console.WriteLine(result); Console.ReadKey(); } static ArrayList array(string str) { ArrayList aimArr = new ArrayList(); ArrayList strArr = new ArrayList(); string [] strs=str.Split(','); foreach (string s in strs) { strArr.Add(s); } for (int i = 0; i < strs.Length; i++) { if (!aimArr.Contains(strs[i])) { aimArr.Add(strs[i]); } } return aimArr; } } //101,102,103,104,105,106,107,108
方法三:使用正则
string input = "101,102,103,104,105,101,102,103,104,105,106,107,101,108"; input = Regex.Replace(input + ",", @"(?:([^,]+,))(?=.*?\1)", ""); Console.WriteLine(input.Substring(0,input.Length-1));
本文标题:C# 实现字符串去重
本文链接:https://vtzw.com/post/1051.html
版权声明:本文不使用任何协议授权,您可以任何形式自由转载或使用。
共有 1 条评论
发表评论 / 取消回复